Question

I NEED HELP WITH QUESTIONS #7 & #8 PLEASE! :)

Capacitor Plot: Current Peak- 132.239 mA , 111.495 ms Voltage Peak- 105.232 V , 123.975 ms

Resistor Plot: Current Peak- 132.239 mA , 111.495 ms Voltage Peak- 132.239 V , 131.335 ms

A/C source Plot: Current Peak- 132.238 mA , 101.575 ms Voltage Peak- 169 V , 102.535 ms

► 07: How does the location of the current peak compare to the location of the voltage peak in each plot at 100 Hz? (Consider where the peaks occur in time.) 31 ► 08: Why does the resistor voltage increase as impedance decreases?

Answer 1

Q.7

Here the location of current peak is compared with the location of voltage peak is based on the power factor associated with the respective wave forms

So that here,

For,

Capacitor Plot: Current Peak- 132.239 mA , 111.495 ms Voltage Peak- 105.232 V , 123.975 ms

We know that the capacitors current leads the voltage by 90° so that here hence current location here is 90° ahead.

For,

Resistor Plot: Current Peak- 132.239 mA , 111.495 ms Voltage Peak- 132.239 V , 131.335 ms

For the resistance we know that, the current and voltages are in same phase as here there is not any dependecy over the frequency so that here both the location of current and voltage are at same place with respect to time.

For,

A/C source Plot: Current Peak- 132.238 mA , 101.575 ms Voltage Peak- 169 V , 102.535 ms

Now when we consider the both resistor and capacitor then the resultant impedance of the circuit here will be capacitive in nature and depending upon that the current location here will be leading in nature in respect to the location of the voltage wave form.

Q.8

Voltages across the resistance will be given as,

Vr = V - Vc

Now here Vc will b3 given as,

Vc = I× Zc

So that when the impedance Z = sqroot(R²+(1/wc)²)

Decreases then the value of Vc decreases which cause Vr increases hence,

When impedance decreases then voltage across the resistance increases.