Question

24)In the image below, the negative charge is 3cm to the left of the positive charge +Q. The black dot is 3cm to the right of the charge. The electric potential energy between the charges is 30 μJ.

A. If the magnitude of the negative charge is 4x that of the positive charge, what is Q? B. What is the net electric field at the location of the black dot? C. What is the magnitude of the electrostatic force each charge exerts on the other?

Answer 1

Solution negative ta 0.03m -0.03 m potential energy UF 30.41 T A) negative charge = -ya do, P.EE K2,22 30 X 106 9xto?x @хч@ Ja 0.03 Q2 Z 25 x 10-18 0.025 x 10-15 5X10-9 Qr С B) Net electric field E= ÊTE E- ka Klau) + 0,2 n 2 = S810-9 6.03) 4X5x109 6.062 c ) 9 (5555-55 - 5555.55) 20 V So Net electric field at black dot is over Electrostatic forre - kl@) (42) 2,2 F = 9x109 x 5x10-9 (0.0312 IX10-3.N force on charge is 1x103. x4x5X10-9 FI fo