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4.7kg block is pulled up a frictionless inclined plane by a 69.0 N force that is...

4.7kg block is pulled up a frictionless inclined plane by a 69.0 N force that is parallel to the plane, starting from rest. the normal force on the block from the plane has magnitude 19.1 N. What is the blocks speed when its displacement up the ramp is 3.7m?

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Answer #1

3.7 m Mgcose Mamaso M 4.7kg 69N force F = normal force N 19.IN Mg = force due force due to gravity Normal force act component of My againstdisplacement 3.7 m v²_u² = = 203 u=0 V = ? F- Mg sino 3.7m 2 as 2x 69 9.8 sino 4.7 2 x 69 9.84 0.91 4.7 29.36 8.92 Y 20,44 (2all the best.

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