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Question 24 of 31 > You have a lens whose focal length is -5.87 cm. You place an object on the axis of the lens at a distance of 12.3 cm from it. How far is the object's image from the lens? Enter the answer as a positive quantity image distance: cm If it can be determined, is the image real or virtual? Oreal cannot be determined

Answer 1

focal length f=-5-87 em (concave lens) object distance (U)=-12.3 cm Let image distance = u>2f Lens formula 1 -& lo VE uf = (-12-3)(-5-87) -3.97 em utf -12-3-5-87 Image distance 13.97 Image is ovirtual 1 f lu - 23 Power , p = 100 D f 41-67 cm .: f 106 2-4 21) tot focal length f = 6.47cm (convex lens) height of object =7-39 mm = 73.9 cm Dbject distance (u) = -13.1 em f 14 b = 5 + uf E13-1) (6-47) utf 13.1 +6:47 =+13.27 cm 6 Image is peal. u> f o image is real please give a Comment pating help me. any doubt sure help. CS Scanned with CamScanner

B M B' A P A En 2 A' F KI PF, = PF 2 Fig. 8.19. Image formed by concave lens when object is placed beyond F2. CS Scanned with CamScanner

B M Er 2F A' 2 A 2F F P. B' Fig. 8.15. Image formed by convex lens when an extended object is placed beyond 2F1. CS Scanned with CamScanner