Question

what am I doing wrong for two that are wrong?

The length of nylon rope from which a mountain climber is suspended has a force constant of 1.70 x 104 N/m. (a) What is the frequency at which he bounces, given his mass plus equipment to be 84.0 kg? 2.26 Hz (b) How much would this rope stretch to break the climber's fall, if he free-falls 2.00 m before the rope runs out of slack? 44 x Can you determine the kinetic energy of the climber at the instant when the rope runs out of slack? As the rope stretches, what types of potential energy are important? m (c) Repeat both parts of this problem in the situation where twice this length of nylon rope is used. bounce 1.601 Hz frequency 0.622 distance How is the force constant for the new longer rope related to the force constant for the shorter rope? Can stretched you find a way to modify your expression for the stretch of the shorter rope from part (b) in order to determine the stretch for the new longer rope? m

Answer 1

k = 1.70x104 Nim m - 84.0 kg a frequency f 1 1 5 h 1.7x104 84 2 r 2.26 Hz Ans D using conservation of energy The PE equal stored in the stretched nylon rope will be Potential energy (PE) due to decrease (x+2) m TOSS in position height xx? = mg (2+2) 2 2 11.7x104) 362 84(9.8) (x+2) (8.5 X 10%j%?- 823-24 - 823-2 Ans x = o. 36 m C twith half length twice then constant fore will be so K = 8.5 x 103 Nim frequency fa ş 8.9 x103 f = 1.60 HZ Ans 27 84.0 d K x 2 mg (x+2) 2 1 (8.5x103) *? = (84) (9.8) (x+2) 4250 x² - 823-2x - 823.2 X - Os 47 m And CS Scanned with CamScanner