2) Determine the equation of the given graph of a hypberola: у $ (0.9) (-15.0) (15.0)...
Determine the equation of the graph of the given pa 2 axis of symmetry + 2 4 6 focus parabola -2+ vertex directrix -4
Question 17 op Write the equation of the parabola x2 + 2.c + 12y - 47 = 0 in standard form. Find the vertex, focus, directrix, axis of symmetry, and latus. Then graph and label your input on the graph. Write the equation of the parabola 32 + 2x + 12y - 47 = 0 in standard form. Find the vertex, focus, directrix, axis of symmetry, and latus. Then graph and label your input on the graph.
Write down the equation of given parabola x? +8x+4y+12 =0 in standard form. State the vertex, focus and the equation of the directrix. Hence, sketch its graph. 4. Show that y² + 4y +8x + 12 = 0 represents a parabola. Hence, determine its focus, and directrix. [4 marks]
Determine whether the given equation represents an ellipse, a parabola, or a hyperbola. If the graph is in ellipse, find the center, foci, vertices, and length of the major and minor axes. If it is a parabola, find the vertex, focus, and directrix. If it is a hyperbola, find the center, foci, vertices, and asymptotes. Graph the equation. 4.2 + y2 – 16x + 6y + 16 = 0
Complete the square to determine whether the equation represents an ellipse, a parabola. If the graph is an ellipse, find the center, foci, vertices, and lengths of the major and minor axes. If it is a parabola, find the vertex, focus, and directrix. Then sketch the graph of the equation. 4x^2 +4x − 8y + 9 = 0
Problem 9: Find the equation of the parabola given F (2,-2) and directrix y = 1 Problem 10: Find the focal axis orientation, vertex, focus, and directrix given x = -y2 + 2y - 6
Find the vertex, focus, and directrix of the following parabola. Graph the equation. y? - 2y +x=0 The vertex is (Type an ordered pair.) The focus is (Type an ordered pair.) The equation of the directrix is (Type an equation.) Use the graphing tool to graph the equation. Click to enlarge graph
Find the vertex, focus, and directrix of the parabola. Then graph the parabola.(x-4)2 = 12(y + 2) The vertex of the parabola is _______ (Type an ordered pair) The focus of the parabola is _______ (Type an ordered pair.) The directrix of the parabola is _______ (Type an equation. Simplify your answer.) Use the graphing tool to graph the parabola only.
For the given Parabola (y-5)=16(x+2)^2 , determine: a. vertex b.P c. focus d. equation of directrix
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Question 17 Opt: Write the equation of the parabola x2 + 2x + 12y – 47 = 0) in standard form. Find the vertex, focus, directrix, axis of symmetry, and latus. Then graph and label your input on the graph.