Question

PRINTER VERSION BACK NEXT Question 4 Your answer is partially correct. Try again. Two particles are fixed to an x axis: particle 1 of charge 91 = 2.47 x 10-8 C at x = 19.0 cm and particle 2 of charge 92 = -4.0091 at x = 78.0 cm. At what coordinate on the x axis is the electric field produced by the particles equal to zero? Number Units 3.70 cm the tolerance is +/-2%

Answer 1

② As and Org are of chances are bewmes 2eyO. between them never opposite sigo, eleeme field is Henie and b) to the right of V. chance is to left of a) to the left of quc is not possible %>q. Hence .78cm Х E-o 927-49 m19cm m se Carp) distance from ar which Eleeme field, E=0 Field at P due to a E = ka, k=eleemostana constant xa? Field at e due to Ez = K&2 Kx4&, (98+x)² 78 tu? 1948, (value) As total field E=0 E, Cancells Ez. E = Ez ka k+4q, (78+ x)2 sc² 4 Taking square roof 78 + x)2 2. 78+ x x 2x=78+x x=78cm co-ordinate of P on X-ame. = 78-19) = – 59cm from origin A due to Porennial at Porennial at =Kq 7 K욘 ४ ke due to ke I day d K+(-5ea-ke dezda2d=8 5d asy -C-50), then

Toral porennial at A = ke d ke VA Porennial at B due to a =Kq = ke ४ ad Posenwal ar due to له !! Toral porennal KU, KC-5e) ซ ad VB = ke -kxse -uke ad zd ad =-2ke d VB = -2x9x10x1.6x10-19 4.7x10-6 k=9410?, e=change of elemn=1.641019c (I think this value because value of e is not given) d = 4.7mm = 4.7 xlo-fm VB = -6.128x10-4 volt Porennial difference, v=VA-VB = -(-6.128) = 6.128 xhovale V=0.0006128 volt