Question

I (W/m/m) Intensity vs. position 800 Scenarios: 1 Correct Answer 600 400 200 0 x (cm) 0 5 10 15 20 25 30 40 incident light polarizer 1 polarizer 2 polarizer 3 I = 800.0 W/m^2 I = 400.0 W/m^2 I = ???? W/m^2 I = 149 W/m^2 polarizer 1 = 98 degrees polarizer 3 = 170 degrees The goal is to figure out the angle of polarizer 2. When you know what it is, set the polarizer 2 slider to that value and then check your answer. polarizer 2 = 0 degrees
find the angle for polarizer 2

Answer 1

be o angle between Let the the angle polarizer 1 & 2 and angle between polarizer 2 & 3 be be ol @ +0' = 170°-989 = o'= 72-0 Intensity of light passing after and Polarizer = 400 cash W/m² malus law : I = To Costo I= to cos?o]

E14.9 Intensity of light passing aftor polarines 3 = (400 cos²o] cos²o => 460 (60520)603262-0)) = 14.9 o cos² (72-0) => O=79° (Hit and trical method) Achal angle ,x= 79°t q8° Angle of the polonizar 2 is 2 → = 0.03725 177° Answer