Question
A beam of unpolarized light with intensity I 0 falls first upon a polarizer with transmission axis theta TA,1 then upon a second polarizer with transmission axis theta TA.2 where theta TA,2 - theta TA,1 =90 degrees in other words the two axes are perpendicular to one another) What is the intensity I 2 of the light beam emerging from the second polarizer? ( Figure 4) Express your answer as a decimal number times the symbol I 0 For example, if I 2 =(1/4)I 0 enter

Part F Notice that a polarizer modifies the light intensity according to Maluss law and also reorients the polarization angl
Expres View Incident natural light 45° 90° 10 Submit Polarizer 1 Polarizer A Polarizer 2 Provide Feedback JUN
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Answer #1

the The intensity after passing polarizen is I = To 2 after passing polarizen A IA = I, cosus = lox 2 Io IA 6 : Iz= IA cos hu

> Thanks!

soap Thu, Dec 9, 2021 5:11 PM

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