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This Question: 5 pts 1 of 26 (14 complete) In the following problem, the expression is the right side of the formula for cos(

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Answer #1

a)

cos\left (\frac{\pi }{12} \right )cos\left (\frac{-\pi }{12} \right )+sin\left (\frac{\pi }{12} \right )sin\left (\frac{-\pi }{12} \right )

Cos\left ( \alpha -\beta \right )=cos\alpha cos\beta +sin\alpha sin\beta
The value of \alpha =\frac{\pi }{12}

The value of \beta =\frac{-\pi }{12}

b)

The expression cosine of anangle

cos\left ( \frac{\pi }{12}- \left ( -\frac{\pi }{2} \right )\right )

=cos\left ( \frac{\pi }{12}+\frac{\pi }{12}\right )

=cos\left ( \frac{2\pi }{12}\right )

=cos\left ( \frac{\pi }{6}\right )

c)

cos\left (\frac{\pi }{12} \right )cos\left (\frac{-\pi }{12} \right )+sin\left (\frac{\pi }{12} \right )sin\left (\frac{-\pi }{12} \right )=cos\left ( \frac{\pi }{6}\right )

                                                                                     =\frac{\sqrt{3}}{2}

e

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