Question

What is the current through the 6 12 resistor? 4V 202 WW 37 602 thun Now choose from one of the following options Why a 0.5 A b 115 C 2.0

Answer 1

Appling Kirchhoff's loop rule to loop abc da +6 -I x 6 3=0 262 => I = 0, SA 37 Answer (a) d tim I

لم \\ Applying Kirchhoff's Loop rule abefa e b Loop w 300 c +5 +30 I, To = 0 -0.4 A I ova A 5V 10 V 50-167 A d Iz= 1,+ Iz = 0.567 A Now, for loop abcda: ts - Iz R=0 -> R=s 0.567 = 8.82 R Answer