Question

1) Find all solutions to the equation sin2x-sinxcosx=cosx upon the interval of [0,2pi)

2) Using the rectangular equation of x²=4y , convert it to polar form.

Answer 1

cox elven We know sinax- sinx cor = that sinax= 2 sinxcosx. 2 sinxros- sina cosa cosu=0 sinx-cosx-cosu=0 cosa (sinu -1)=0 cosx=0 gina -1=0 sina=1

Take CASO TL 211, *- 39+216 cine Bolutions for the range [0, 211) = 311 sind 1 1 + win Solutions for the range 2 combining and 1 = 1 / 1 BTT Therefor, solutions ase 1 = - X= 31 is x = 44 Given that sechangulos equation In polas form, we know X=44 x = 8 noso and y=rsino. substitute these values in -> (280) = A (rino) - scoso = 48 sino rcoso = 4 sino Heino costo = 4 sino coso cole 4 tano seco. Therefore, polar form of given equation is 7 eine coso (oh) of caso = 4 sino ce YEH tano seco.