Given equation is: H2 + O2 —> H2O
Here in left side of the equation:
Number of H atom is 2
Number of O atom is 2
In right side of the equation:
Number of H atom is 2
Number of O atom is 1
Thus, O atom is not balance and to balance we have to multiply 2 in right side.
H2 + O2 —> 2 H2O
Now, in right side number of H atom is 4 thus to balance it with left side we have to multiply 2 with H2 in left side.
Now,
2 H2 + O2 —> 2 H2O
Now, this reaction is balanced.
Hence, balanced reaction is:
2 H2 + O2 —> 2 H2O
QUESTION 14 Balance this equation: H2 + O2 -> H2O 3H2 + O2 + 5H2O 2H2...
The equation H2+O2 arrow to the right H2O be balanced by changing it to: A. H2+O2 arrow to the right H2O2 B. 2H2+O2 arrow to the right 2H2O C. Nothing needs to be done; it is already balanced D. H2+2O2 arrow to the right 4H2O
Given the thermochemical equation for the formation of H2O by burning H2 and O2: H2(g) + 402 (8) → H2O (8) ΔH° = -241.8 kJ Calculate the ΔH for the following reaction: 2H2O (g) → 2 H2(g) + O2 (g)
From the following balanced equation, 2H2(g)+O2(g)⟶2H2O(g) how many molecules of H2O can be formed from 5.58mol H2?
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The following thermochemical equation is for the reaction of hydrogen(g) with oxygen(g) to form H2O(g). 2H2(g) + O2(g) 2H2O(g) AH=-484 kJ How many grams of H2(g) would have to react to produce 61.5 kJ of energy? grams
QUESTION 1 Balance the equation: Al203 02 Al QUESTION 2 Balance the equation Hа0 CO2 O2 -> C2H6 QUESTION 3 Balance the equation: Caso4 Al(OH)3 Caа(ОН)2 Al2(S04)3 + QUESTION 4 Which chemical equation is properly balanced? 2 SO2 O2 2 H30 -2 H2SO4 so2+O2+ H20> H2$O4 So2+O2+4 H202 H2SO4 4 SO O24 H20-4 H2SO4 answers
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Use Hess's law to determine A.Hº for the reaction C3H4(g) + 2 H2(g) -> C3H8(8), given that Hy(8) + O2(8) — H2O(1) A Hº = -285.8 kJ mol-1 C3H4(8) + 402(g) — 3 CO2(g) + 2 H2O(1) A Hº = -1937 kJ mol-1 C3H2(g) + 5O2(g) — 3CO2(g) + 4H2O(1) A Hº = -2219.1 kJ mol-1
Question 2 (1 point) E Which is not a redox equation? H2SO4 + Na2CO3? Na2SO4 + CO2 + H2O 2H2 + O2 ? 2H2O all are redox equation:s NaClO + KMnO4 ? NaClO3 + KM nO2 Save Previous Page Next Page Page 2 of 20 enoVO ?>< 1? ?+ 6 8 0
QUESTION 7 Consider the reaction below. CO(g) + 3H2 (g) CH4(g) + H2O(g) Kc 138 at 1200 K 0.2 mol of CO and 0.3 mol of H2 gas are initially placed in a 1.0 L container. Letting X -concentration of CO reacted leads to the following equilibrium expression. (0.2-x)(0.3-3x) Solving for X gives the following roots x = 0.209045 x-0.107165 +0.0316478 x-0.107165-0.03 16478/ x0.0766248 What is the equilibrium concentration of CH4 in molar? QUESTION 8 Click Save and Submit to...