Given the thermochemical equation for the formation of H2O by burning H2 and O2:
H2(g) + 402 (8) → H2O (8) ΔH° = -241.8 kJ
Calculate the ΔH for the following reaction:
2H2O (g) → 2 H2(g) + O2 (g)
Given the thermochemical equation for the formation of H2O by burning H2 and O2:
The following thermochemical equation is for the reaction of hydrogen(g) with oxygen(g) to form H2O(g). 2H2(g) + O2(g) 2H2O(g) AH=-484 kJ How many grams of H2(g) would have to react to produce 61.5 kJ of energy? grams
The specific heat of copper is 0.385 J/(g∙°C). If 34.2 g of copper, initially at 25°C, absorbs 4.689 kJ, what will be the final temperature of the copper? a. 25.4°C b. 27.8°C c. 356°C d. 381°C A chemical reaction causes the temperature of 1.0 x 102 g of water in a calorimeter to rise from 25°C to 40°C. The specific heat of water is 4.184 J/(g∙°C). What is the heat of reaction, qP? a. -0.31 kJ b. -0.75 kJ c....
The specific heat of copper is 0.385 J/(g∙°C). If 34.2 g of copper, initially at 25°C, absorbs 4.689 kJ, what will be the final temperature of the copper? a. 25.4°C b. 27.8°C c. 356°C d. 381°C A chemical reaction causes the temperature of 1.0 x 102 g of water in a calorimeter to rise from 25°C to 40°C. The specific heat of water is 4.184 J/(g∙°C). What is the heat of reaction, qP? a. -0.31 kJ b. -0.75 kJ c....
Thermochemical equations 5. Given 2NO → N2 + O2 ∆H= -180.7 determine the enthalpy of the reverse reaction? Is the reverse reaction endothermic or exothermic? 6. Given H2 + F2 → 2HF ∆H= -537 kJ a) How much heat is required to react 9.5 g F2 with H2? b) What mass of H2 is needed to react with F2 with -294 kJ of energy? Hess Law State Hess’s Law 8. Use the standard reaction enthalpies given below to determine ΔH°...
Given these reactions, where X represents a generic metal or metalloid 1) H2(g)+12O2(g)⟶H2O(g)Δ?1=−241.8 kJ1) H2(g)+12O2(g)⟶H2O(g)ΔH1=−241.8 kJ 2) X(s)+2Cl2(g)⟶XCl4(s)Δ?2=+157.3 kJ2) X(s)+2Cl2(g)⟶XCl4(s)ΔH2=+157.3 kJ 3) 12H2(g)+12Cl2(g)⟶HCl(g)Δ?3=−92.3 kJ3) 12H2(g)+12Cl2(g)⟶HCl(g)ΔH3=−92.3 kJ 4) X(s)+O2(g)⟶XO2(s)Δ?4=−769.5 kJ4) X(s)+O2(g)⟶XO2(s)ΔH4=−769.5 kJ 5) H2O(g)⟶H2O(l)Δ?5=−44.0 kJ5) H2O(g)⟶H2O(l)ΔH5=−44.0 kJ what is the enthalpy, Δ?,ΔH, for this reaction? XCl4(s)+2H2O(l)⟶XO2(s)+4HCl(g)
Calculate the standard enthalpy of formation of liquid water (H2O) using the following thermochemical information: CH4(g) C(s) + 2 H2(g) H = +74.8 kJ CO2(g) C(s) + O2(g) H = +393.5 kJ CO2(g) + 2 H2O(l) CH4(g) + 2 O2(g) H = +890.4 kJ
Calculate the standard enthalpy of formation of liquid water (H2O) using the following thermochemical information: 2 HNO3(l) N2O5(g) + H2O(l) H = +92.0 kJ 2 N2(g) + 5 O2(g) 2 N2O5(g) H = +59.3 kJ N2(g) + 3 O2(g) + H2(g) 2 HNO3(l) H = -348.2 kJ
Question 3 Propane (C3H8) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) -- 3 CO2(g) + 4H2O(g) Arxn = -2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3H8 a. -104.7 kJ/mol ob. +1407.7 kJ/mol C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol
Calculate the standard enthalpy of formation of liquid water (H2O) using the following thermochemical information: 2 B2O3(s) 4 B(s) + 3 O2(g) H = +2509.1 kJ B2O3(s) + 3 H2O(l) B2H6(g) + 3 O2(g) H = +2147.5 kJ 2 B(s) + 3 H2(g) B2H6(g) H = +35.4 kJ H = ______ kJ
QUESTION 14 Balance this equation: H2 + O2 -> H2O 3H2 + O2 + 5H2O 2H2 + 202 + 4H2O 2H2 + O2 + 2H2O H2 + 402 - 3H2O Click Save and Submit to saue and submit. Click Save All Answers to sau. . 99+ AS