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23.- Calculate AU for a process that takes 1.0 mol of argon from T = 298.15 K and V = 2.0 L to T = 373.15 K and V = 20.0 L. A

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23 T = 298.1sk, Tze 373.15k nzimole cu 2 3 3 R Rz 8.311 Jl kimo AU naz ДТ U z nGoT |x 3 Rх Rx 373-15—298.15) 22 23x8.314 Il m

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