Question

need help with these asap

Question 10 Choose the correct numerical value for the molarity from the response list for a solution using 50.0 mL of 0.40 M solution diluted to a final volume of 0.400 L. 0.050 M 8.0 M 3.20 M O 0.10 M 2 pts Question 11 A 0.300 M solution of LiOH that contains 0.600 mole of solute would have a volume, in milliliters, of 1.67 x 10 ml 30.0 mL 6,00 x 10-ml. 2.00 x 10 ml

Answer 1

Initial concentration of solution ,M,= 0.40 turial Concentration of folnton, M2 = M Initial volume of solution, , 50 me 50 x103 L Final volume of solution, 4 0.400L now number of moles of solute = molarity xolume humber moles of solute before dilution = Moyo (ni2) = 0.40850 xlot Simil number moles solute e of similarly of of after dilution = Malla (miL) number moles Now constant of in the process of : Mx0.400 of solute remains dilntion ? tune ho moles of solute (Before dilunon) No of moles of sointe (after dilution) = No Mivi M₂ V2 0.40% so xio3 MX0.400 0.40x50 x103 50x103 - - 050M M - 0.noo oll a solution = number Number of moles of solute Molarity of volume of sohntion (ii) Molarity = 0.300M of moles of solute = 0.600 Number of moles of shule - 0.600-2 solution (L) Molarity Wlume of solution = 2L = 2x103mi Wlume 0.300