Question

SUTULIUTIS Exercise D Calculating Molarity Concentration (1 pt per answer, 10 total) Complete the following table by calculating the molarity for the following solutions. The molarity is the number of moles of the solute divided by the volume of the solution in Liters. Use the molecular mass of the solute to calculate the moles if you only have the mass of the solute. Fill in all of the empty columns. The volume must be in Liters. Mass of solute Moles of solute 50.0 grams 400. grams 100. mg Molecular mass of solute 150. grams/mole 200. grams/mole 35. grams/mole 300. grams/mole 55.0 grams/mole (Liters) 1.00 L 250. mL 2.30 L 0.25 moles 0.75 M 0.0100M 250 mL

Answer 1

Moles = - Molarity - No of moles of solute 0 vot of solution in Litres gewen Mass Molecular Mass 20. Makany dohub = = (0.33 own :10.33 Molen = 100,- Molarity = 2 = [8M = FORME Barbertes o "100.0 20.1 - 2.30 Groven volume = 1.000 4 - Noor Mole, 9 0:33 - 10.33M o voluúo 1) Moles of solule ;-) Чоо, - 2 Mous ) 200 As I lite = 1000 ml) Griveer volume = 250ml Iml = tool ; 30.256 250ml= 250 106d 0.25 = 0.25L) Mass of solute = loom = 100 g = 0.1 - Moles= 0=1.00286 Given volume = 2.301 ;. Molarity =0.0086 +0.00124 m) - --- ---- - (niven, moles 0.25 : Mass of = Moles & Moleulan = 0.25% 300 = 75 gram Molarity = 0.75 : Volume = Molanty & Male = 0.75 x 0.25 -2.5 0.18727 Graemer , Moles - Molarly x volums = 0.0100 x 250 100 X 230 = 0.0025 Moles Too 1000 L Mass of solute - Moles & Moleculer man = 0.0025 x 55 -10.131512 D Mass of solute Moleculer Mass Mole of Salute Voleum of Solvent i Molarity @ 500g 150 g/mole 0-33 Moles 2002 | 200 g/mole | 2 Moles 8 M 35 gl mole 0.00286 Moles 2-30L 0.00124 m. 300 g/mole 0.25 Moles 0.187L 0-75M 0.1375g ss glmale | 0.0025 250mL 0.0100 M 1. Moles Soleile u " Mars 0.33 M 250 ml noog 100mg zsg