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The volume to reach the first equivalence point for a diprotic acid is 14.66 mL Determine...
How to calculate the moles of diprotic acid H2X to reach the first and second equivalence points? Then used the moles of the diprotic acid to calculate the moles in the origional 100.0 Ml of solution. remmeber that you titrated 25.0 mL of the solution. information given: 4.9 mL of NaOH required to reach first equivalence point 9.9 mL of NaOH reuired to reach second equivalence pont 5.0421*10-4 moles of NaOH required to reach first equivalence point 1.01871*10-3 moles of...
7. If the second equivalence point in the titration of a diprotic acid is at 39.48 mL of strong base titrant added, at what volume is the? robudno b First half-equivalence point? Second half-equivalence point? iniog solving First equivalence point? Second equivalence point? 39.48 mL
DETERMINATION OF MOLECULAR WEIGHT OF AN UNKNOWN DIPROTIC ACID Use Data Set to answer the following questions 1. Using the data, sketch a titration curve for the titration of the acid with 0.1 M NaOH pH 0 volume of NaOH added 2. Using the first equivalence point, determine the molecular weight of the acid. Use the sequence of steps employed in the in-class exercise. Homework Molecular Weight of an Unknown Diprotic Acid 3. Using the second equivalence point, determine the...
Titration of 25.00 mL of an unknown diprotic acid solution required 15.09 mL of 0.10 M NaOH to reach the first equivalence point and 29.82 mL of 0.10 M NaOH to reach the second equivalence point. What is the concentration of the diprotic acid solution?
a) Use this plot to estimate the volume of NaOH required to reach the equivalence point of each titration curve. b) Estimate the original concentration of weak acid in solution before strong base was added. c) Find the midpoint pH for each of the trials using half the volume of NaOH required to reach the equivalence point for that trial. Check if this pH is at the most flat part of the titration curve. This is the pKa of the...
Please refer to data set D 1. For each data set, the volume of acid being analyzed is 10.00 mL and the concentration of NAOH is 0.100 M. 2nd Volume of pH at 1st eq. pt pH at pt Conc. of Volume of Data Set eq. acid (g/L) NaOH at 1st NAOH at 2nd eq.point (mL) eq.point (mL) 9.12 4.1 15.98 9.6 8.06 9.2 15.12 11.95 4.3 24.09 В 3.9 18.10 12.42 8.96 8.8 С D 21.00 14.08 27.96 9.1...
Determine the volume in mL of 0.45 M HClO4(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 35.2 mL of 0.31 M CH3CH2NH2(aq). Enter your answer with one decimal place. The Kb of ethylamine is 6.5 x 10-4.
Imagine the titration of 50.0 ml of 0.100 M aluminum chloride with 0.200 M silver carbonate. Calculate the volume of silver carbonate necessary to reach the equivalence point (Ve), then calculate the concentration of Ag+, Cl-, and pAg after addition of the following volumes of silver carbonate a. half of the volume required to reach the equivalence point, (0.5 Ve)b. the volume necessary to reach the equivalence point, (Ve)c. 10 ml beyond the volume necessary to reach the equivalnce point, (Ve+10...
What volume of 1.0 M of NaOH (in mL) is needed to reach the second equivalence point when titrating 100 mL of 0.12 M phosphoric acid?
Determine the volume in mL of 0.57 M HNO3(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 37.9 mL of 0.5 M CH3NH2(aq)(aq). The Kb of methylamine is 3.6 x 10-4. Enter your answer with two decimal places and no units. (how is the answer 16.62?)