Question

КИХр. Data Sheet Moles of acetic acid contained in 50.0 mL of a 0.10 M sample solution: 0.00 Smule 50.0mL XL -> 0.05-24 0.1om Buffer pH Study 1000mL IL Buffer Sample initial pH: 4.71 buller. DH and kavalehe Sume. How mane marremalol pH after addition of 0.100 M HCI Mass of sodium acetate needed to equalize the moles of acetic acid in sample solution: 0.419 = 0.005 moles X 829 = 0.419 Inclenche pH after addition of 0.100 M NaOH pH Total volume added PH Total volume added Od 4.75 1.00 mL 4.68 1.00 mL 4.80 2.00 mL 4.62 2.00 mL 9 4.84 3.00 mL 4.57 3.00 mL - 4.00 mL 4.89 4.51 4.00 mL ain 5.00 mL 4.94 5.00 mL 4.46 Diluted Buffer Sample initial pH: 4.82 pH after addition of 0.100 M NaOH pH after addition of 0.100 M HCI Total volume added pH pH Total volume added 4.46 1.00 mL 1.00 mL 4.95 Hoges 4.15 2.00 mL 2.00 mL 5.24 3.00 mL 3.38 2m 5.69 3.00 mL 4.00 mL 10.93 Oclc.hu tally 2.49 decreasing 4.00 mL 4 bum n 2.17 5.00 mL 11.67 5.00 mL Lomatar Inih Gud ImL Lo you Adela rhoease Is Wher conceny Ok Base Bu Initial pH of unbuffered HCl: 2.89 pH after addition of 1.0 ml NaOH: 10.10 The maximum amount of Base that can be acced eacare to the Amant of week Acica presen an the - Butter When Naot is added it reacts with accenc Acid to Convert Sodium Acetale max amant ok. Nagh that can be accruce, = moles of Acenc teid =0.005 indled Comaci / modes of Nont = 0.005 mcles

how to calculate the buffer capacity and how can i solve the properties of buffer 2 solution. i already some calculations put im not sure if I'm correct