Question


Part A From the value K-1.2 x 10 for NI(NH), luate the concentration of NH, required to just dissolve 0.026 mol of NIC,O (K 4
brunconden Using the Ky value of 1.2 x 10 calculate the concentration of NP (n) and NI(NH), that are present at equilibrium
0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
Part A From the value K-1.2 x 10 for NI(NH), luate the concentration of NH, required...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • Part A Using the Ky value of 1.2 x 10 calculate the concentration of N() and...

    Part A Using the Ky value of 1.2 x 10 calculate the concentration of N() and NI(NH)," that are present at equilibrium afer dissolving 1.38 g NICI, in 1000 mL of NH,() solution such that the equilibrium concentration of NH, is equal to 0 20 M Express your answers in moles per liter to two significant figures separated by a comma. 10 AED N) - M Your submission doesn't have the correct number of answers. Answers should be separated with...

  • Using the value of 1.2 x 10 calculate the concentration of Ni?" (aq) and NINH)," that...

    Using the value of 1.2 x 10 calculate the concentration of Ni?" (aq) and NINH)," that are present at ultriun afer dissolving 110 8 NICI, 1 100.0 ml of NH, (nsolution such that the oqulibriun concentration of NH, is equal to 0.20 M Express your answers in moles per liter to two significant figures separated by a comma. 80 AED ? XOR INILININH, M Submit Previous Answers Request Answer

  • i need help woth this!! Part A K. From the value Ke = 1.2 x 10°...

    i need help woth this!! Part A K. From the value Ke = 1.2 x 10° for Ni(NH3).2+, calculate the concentration of NH3 required to just dissolve 0.024 mol of NiC 04 (K,p = 4 x 10-1) in 1.00 L of solution. (Hint: You can neglect the hydrolysis of C,0,2- because the solution will be quite basic.) Express your answer using two significant figures. Iyo AEO ? (NH3) = 0.37 M Submit Previous Answers Request Answer

  • Part A Using the Kr value of 1.2 x 109 calculate the concentration of Ni2+ (aq)...

    Part A Using the Kr value of 1.2 x 109 calculate the concentration of Ni2+ (aq) and Ni(NH4)6 that are present at equilibrium after dissolving 1.73 g NiCl, in 100.0 mL of NHs (aq) solution such that the equilibriuin concentration of NH3 is equal to 0.20 M. Express your answers in moles per liter to two significant figures separated by a comma VO AED ? |N12"). [Ni(NH3).**] - M Submit Request Answer

  • need help with rhis!!! Part A 24 Using the Kr value of 1.2 x 109 calculate...

    need help with rhis!!! Part A 24 Using the Kr value of 1.2 x 109 calculate the concentration of Ni2+ (aq) and Ni(NH3) that are present at equilibrium after dissolving 1.73 g NiCl2 in 100.0 mL of NHs (aq) solution such that the equilibriun concentration of NH3 is equal to 0.20 M. Express your answers in moles per liter to two significant figures separated by a comma. VOAE ? |N124). [Ni(NH3).”+] - M Submit Request Answer

  • can someone help me out!! Part A Using the Ke value of 1.2 x 109 calculate...

    can someone help me out!! Part A Using the Ke value of 1.2 x 109 calculate the concentration of Ni2+ (aq) and Ni(NH)that are present at equilibrium after dissolving 1.73 g NiCl2 in 100.0 mL of NH3(aq) solution such that the equilibrium concentration of NH3 is equal to 0.20 M. Express your answers in moles per liter to two significant figures separated by a comma. O AE ? Xy vx x x (X X x 10 ex [Ni2-1. [Ni(NH3)621 0.13,1.0...

  • i need help with this!!! You may want to reference (Pages 744 - 750) Section 17.5...

    i need help with this!!! You may want to reference (Pages 744 - 750) Section 17.5 while completing this problem. Part A From the value K; = 1.2 x 10 for Ni(NH3 )e2+, calculate the concentration of NH, required to just dissolve 0.024 mol of NiC204 (Ksp = 4 x 10-19) in 1.00 L of solution. (Hint: You can neglect the hydrolysis of C,0, because the solution will be quite basic.) Express your answer using two significant figures. VOAD ?...

  • Part A Consider the reaction 10, (aq) + 2H20 (1) H.10, (ag): K. - 3.5 x...

    Part A Consider the reaction 10, (aq) + 2H20 (1) H.10, (ag): K. - 3.5 x 10-9 If you start with 23.0 mL of a 0.903 M solution of Nalo, and then dilute it with water to 500.0 mL, what is the concentration of H, 10, at equilibrium? Express your answer to two significant figures and include the appropriate units. A ? Value Units Submit Request Answer Provide Feedback

  • The value of K., for Mgs (Asoc)2 is 2.1 x 10-20. The Aso,-ion is derived from...

    The value of K., for Mgs (Asoc)2 is 2.1 x 10-20. The Aso,-ion is derived from the weak acid H, AsO (pK1 = 2.22; p 2 = 6.98; pK3 = 11.50). Part A Calculate the molar solubility of Mgs (Asoc), in water. Express your answer to two significant figures and include the appropriate unit НА ? Value Units Mgs (AsO4)2 Submit Request Answer Part B Calculate the pH of a saturated solution of Mg (AsO4)2 in water, Express your answer...

  • i need help with part B The value of K., for Mga (AsO.)te 2.1 x 10-20...

    i need help with part B The value of K., for Mga (AsO.)te 2.1 x 10-20 The Asion is derived from the weak and HASO ipka - 2.22: pk-6.98p - 11.50). Part A Calculate the molar solubility of Mg (AsO)in water Express your answer to two significant figures and include the appropriate units. 4.5x10-6 Mg(A:0) Previous Answers ✓ Correct Part B Calculate the pH of a saturated solution of Miga (AO) in water. Express your answer in terms of pH....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT