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Question 9 What is the equilibrium expression for the following reaction? PCls (9) PC13 (9) +...
What is the equilibrium expression for the following reaction? PCl; (g) PC13 (9) + Cl2 (g) Keq [PC13][C12] [PC15] Keq = [PC13] [C12]2 [PC15] Keq [PC13] [PC15] Kea [PC13)(C12] [PC15] Keq [PC13) (C12] [PC15]
Answer the questions about the following reaction below. The equilibrium constant for the decomposition of PCls at 250°C is 0.041 ΔH is positive; reactants and products are gases at 250°C. Refer to your textbook. 1. Is the reaction above exothermic or endothermic? 2. What happens to the concentrations of PCls and Cl if more PCls is added once the reaction reaches equilibrium? (increases, decreases) PC1s Cl2 3. What happens to the moles of PCIs, PCls and Cl in the container...
The equilibrium constant, K, for the following reaction is 3.52*10 at 528 K PC13(g) =PC12(g) + Cl2(g) An equilibrium mixture of the three gases in a 9.42 L container at 528 K contains 0.244 M PCIE. 9.27X10-2M PCI, and 9.27-10-2M Cly. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 17.1 L? M [PC15] [PC13] = [Cl] M M
Part B please For the equilibrium reaction: PCI (g) =PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibrium equation for the reaction. [1 mark] b. If 2.0 gram of PCis(g) is introduced into a 1.5 L flask what will be the equilibrium concentrations of PCls, PClz and Cl ? [4marks]
Consider the reaction. PC15(g) 근 PC13(g) + Cl2(g) K = 0.042 The concentrations of the products at equilibrium are PC, l = 0 10 M and [CI| = O. 1 3 M What is the concentration of the reactant, PCl, at equilibrium? PCI,I
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC15(g) Calculate the equilibrium concentrations of reactant and products when 0.389 moles of PC13 and 0.389 moles of Cl2 are introduced into a 1.00 L vessel at 500 K [PC13] = [Cl] = [PC15] - The equilibrium constant, Kc, for the following reaction is 5.10x10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibrium concentration of HCl when 0.467 moles of NHACI(S)...
ampere The reaction, PCls (g) 5 PC13(g) + Cl2(g), has Kc = 4.20 x 102. If 0.1050 mol of PCL5, 0.0450 mol of Cl2 and 0.0450 mol of PCl3 is placed in a 0.5000-L flask at 250°C, what are the equilibrium concentrations of PCl3 and Cl, if equilibrium (PCI5] = 0.2065 M? A) [PC13] = 0.00350 M; (Cl2] = 0.00350 M B) [PC13] = 0.0900 M; [Cl2] = 0.0900 M -=51,85 (66450) (19450) C) [PC13] = 0.2100 M; [Cl2] =...
Phosphorus pentachloride decomposes according to the chemical equation PC15(g) PC13(g) + Cl2 (g) Kc = 1.80 at 250° C A 0.475 mol sample of PCI, (g) is injected into an empty 4.90 L reaction vessel held at 250° C. Calculate the concentrations of PCI, (g) and PCI,(g) at equilibrium. [PCls] [PCl3]
The equilibrium constant, K, for the following reaction is 1.20x10-2 at 500 K. PC15(E) =PC13(E) + Cl2(E) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.157 M PCI3, 4.34x102 MPC12 and 4.34x102 M CI, What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.17x10 - mol of Cl2(g) is added to the flask? [PC13] = [PC13] = [Cl] =
The equilibrium constant, K, for the following reaction is 5.56×10 2 at 541 K. PC13(g) PC13(e) + Cly(8) An equilibrium mixture of the three gases in a 13.5 L container at 541 K contains 0.245 M PCI, 0.117 M PC13 and 0.117 M CI, What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 6.44 L? M [PC15] = [PC13] = [CI] M...