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How dramoses according to the following reaction: far pa mozten az 298 K. 45 mn =...
Hydrogen sulfide decomposes according to the following reaction: 2008 - 2Hald Sald For this reaction at 298 K, 457xn = 78.1 J/K • Mol, AHrxn = 169.4 kJ/mol, and AG M61k/ima! What is 4 Gan at 900. K? Maple Choice 0-69881 kJ/mol -69881 kJ/mol
Hydrogen sulfide decomposes according to the following reaction, 2 H25(g)2 H2(g)+S2(g) Δ5° = +78.1 J/K, ΔH° = +169.4 kJ. The reaction is spontaneous at O T< 2169 K O T>1891 K O T1891 K T> 2169 K
The standard enthalpy change for the following reaction is 521 kJ at 298 K. MnO2(8) Mn(s) + O2(g) What is the standard heat of formation of MnO()? kJ/mol
Calculate Grxn at 298 K under the conditions shown below for the following reaction. 2 H2S(g) + 3 O2(g) 2 SO2(g) + 2 H2O(g) G°rxn = ? G°f (kJ/mol) -33.4 -300.1 -228.6 P(H2S) = 1.4 atm, P(O2) = 0.5atm P(SO2) = 2.2atm and P(H2O) = 0.8 atm
Calculate the equilibrium constant K at 298 K for the following reaction: 3C2H2 → C6H6 ?G f^o(C2H2) = 209.2 kJ/mol, ?G f^o(C6H6) = 129.7kJ/mol Choices: a.) 3.33*10^95 b.) 2.57*10^45 c.) 6.53 * 10^30 d.) 1.96*10^87
The standard enthalpy change for the following reaction is -971 kJ at 298 K What is the standard enthalpy change for the reaction at 298 K? 4 Mn(s) + 3。2(g)-→ 2 Mn2O3(s) kJ
The following reaction has the thermodynamic values at 298 K: AH° =-136.9 kJ/mol and AS" = -120.6 J/mol K. HаС — СHз (9) Нас— CHz (0) + Hа (0) a. Calculate AG° at 298 K for this reaction in kJ/mol (Enter your answer to four significant figures.) kJ/mol b. The reaction is c. The reaction is.
QUESTION 23 - For the reaction below at 298 K: 4NO (9) N20 (9) + N203 (9) AH = -192.7 kJ and AS = -308.2 J/K Which of the following statements is TRUE? AG >0 at 298K At higher temperatures, the reaction will be spontaneous At lower temperatures, the reaction will be spontAreous The reaction is spontaneous at all temperatures. None of the above are true. QUESTION 24 What is Asº at 298 K for the following reaction? 2 H2S(g)...
HELP PLEASE (a) Calculate AGⓇ for the following reaction at 298 K. The AGP values are 0 kJ/mol for Cl2(e) -325 kJ/mol for PC (e), and -286 kJ/mol for PC13(e). PCIE) - PC3(g) + Cl2(8) (6) Calculate AG at 298 K for the reaction if the partial pressures are PC12 -0.40 atm, PPC13 - 0.27 atm, and PPCIS -0.0029 atm.
() Calculate AGⓇ for the following reaction at 298 K. The AGP values are 0 kJ/mol for C12(e) -325 kJ/mol for Cisce), and -286 kJ/mol for PC13(e). PC1518) PC3(8) + Cl2(g) (b) Calculate AG at 298 K for the reaction if the partial pressures are PC120,40 atm, PPC13 -0.27 atm, and PPCi5 -0.0029 atm.