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Suppose a solution is made containing 7.3 x 10-3 M Sr(NO3)2(aq) and 8.3 x 102 M...
solution 15 made containing 7.8 x 10-3 (Sr(NO3)2) 25.) suppose and 8.3 x10-2 NaF (aq). Calculate Q and determine wheter a precipate lydstupem of SrFe will form. Ksp of SrF2= 2.8x10-9 ppt forms forms no ppt CQ = 2.0 110-4 pot forms ppt no ppt e Q= 6.1810-4 a. Q = 5.0 x10-5 b Q = 5.0 X1D-5 d Q = 6.1 810-4
Will a ppt of SrF2 (s) form if you mix 7.7 x 10-4 M Sr(NO3)2 (aq) with 3.8 x 10-5 M NaF (aq)? (Which of the following is entirely correct?) OQ = 2.9 x 10-8 ppt forms O Q = 2.9 x 10-8, no ppt Q = 1.1 x 10-12, ppt forms O Q - 1.1 x 10-12, no ppt O Q = 4.4 x 10-12, no ppt
Suppose 50mL of 8.4x10-7 M Pb(NO3)2 (aq) is mixed with 200mL of 9.7x10-4 M Na2CO3(aq). Calculate Q and determine whether a ppt of PbCO3(s) will form. (In other words which of the following is entirely correct?) (Suggestion: Write the dissolving equation and Ksp expression for PbCO3 before starting this problem). a. Q=8.1x10-10 , no ppt b. Q=8.1x10-10 , ppt forms c. Q=1.3x10-10 , no ppt d. Q=1.3x10-10 , ppt forms e. Q=2.5x10-9 , ppt forms
96 mL of 0.080 M NaF is mixed with 32 mL of 0.20 M Sr(NO3)2. Calculate the concentration of Sr2+ in the final solution. Assume volumes can be added. (Ksp for SrF2 = 2.0 ×10-10)
12 – A solution of 0.060 M NaF (75 mL) is mixed with 0.15 M Sr(NO3)2 (25 mL). Calculate the concentrations of each ion after equilibrium is achieved given Ksp for SrF2 = 2.0 x 10-10.Hint: The ion exchange reaction to produce SrF2 can be considered to go to completion before equilibrium is reestablished starting from the products, much as we’ve done for titration calculations at the equivalence point 13 – a) Calculate the molar solubility of hydroxyapatite given Ksp...
QUESTION 21 A solution is 0.012 Min Pb(NO3)2 and 0.20 Min Sr(NO3)2. Solid Na2SO4 is added until a precipitate just begins to form. The precipitate is and the concentration of sulfate ion at this point is Ksp for PbSO4 is 1.8 x 10-8 and for SrS04 is 2.8 x 10-7 PbSO4: 1.5 10 M SrS04; 1.4 x 10-6M PbSO4; 6.3 * 10 M "SrS04; 8.3 x 10-?M S-S04:2.6 x 10-7M
You prepare a solution by mixing 400.0 mL of 1 x 10-4 M Mg(NO3)2 and 500.0 mL of 1.00 x 10-4 M NaF. What is the observed outcome? For MgF2, Ksp = 6.4 x 10-9. A. A precipitate forms because Qsp > Ksp. B. No precipitate forms because Qsp > Ksp. C. No precipitate forms because Qsp = Ksp. D. No precipitate forms because Qsp < Ksp. E. A precipitate forms because Qsp < Ksp.
if 125 mL of a solution containing 0.0400 M of Pb(NO3)2 (aq) is mixed with 75.0 mL of a solution containing 0.0200 of NaCl(aq), will there be a precipitate? PbCl3 has a Ksp value of 1.6 x 10^-5. Assume volumes are additive when mixed
QUESTION 18 A solution is made by dissolving 1.0x 10 3 M MgCl2 and 1.0x 10 3 M NaF MgF2(5)# Mg2+ (aq) +2Cl"(aq) Ksp=5.16× 10-11 Will a precipitate of MgF2 form? O Yes, Q< Ksp O No, Q < Ksp O Yes, Q> Ksp O No, Q> Ksp
3. A solution containing potassium bromide is mixed with one containing strontium nitrate to form a solution that is 0.0044 M in KF and 2.1x 10-4 M in Sr(NO3)2. The Ksp for Sifz is 7.9 x 10-10 Does a precipitate form in the mixed solution? If so, identify the precipitate a. Find the precipitate using double replacement reaction. b. Write the chemical equation for the formation of the precipitate omitting the spectator ions: c. Write the following: Chemical Equation: Ksp...