Suppose 50mL of 8.4x10-7 M Pb(NO3)2 (aq) is mixed with 200mL of 9.7x10-4 M Na2CO3(aq). Calculate...
Suppose 50mL of 8.4x10-7 M Pb(NO3)2 (aq) is mixed with 200mL of 9.7x10-4 M Na2CO3(aq). Calculate Q and determine whether a ppt of PbCO3(s) will form. (In other words which of the following is entirely correct?) (Suggestion: Write the dissolving equation and Ksp expression for PbCO3 before starting this problem).
a. Q=8.1x10-10 , no ppt
b. Q=8.1x10-10 , ppt forms
c. Q=1.3x10-10 , no ppt
d. Q=1.3x10-10 , ppt forms
e. Q=2.5x10-9 , ppt forms
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Suppose 50mL of 8.4x10-7 M
Pb(NO3)2 (aq) is mixed with 200mL of
9.7x10-4 M Na2CO3(aq). Calculate...
Suppose a solution is made containing 7.3 x 10-3 M Sr(NO3)2(aq) and 8.3 x 102 M...
Suppose a solution is made containing 7.3 x 10-3 M Sr(NO3)2(aq) and 8.3 x 102 M NaF (aq). Calculate Q and determine whether a precipitate of SrF2 (s) will form. (In other words, which of the following is entirely correct?) Ksp of SrF2 = 2.8 x 10-9 a. Q = 5.0 x 105, ppt forms b. Q = 5.0 x 10-5, no ppt c. Q = 2.0 x 104 ppt forms d. Q = 6.1 x 104.ppt forms e. Q...
Will a ppt of SrF2 (s) form if you mix 7.7 x 10-4 M Sr(NO3)2 (aq)...
Will a ppt of SrF2 (s) form if you mix 7.7 x 10-4 M Sr(NO3)2 (aq) with 3.8 x 10-5 M NaF (aq)? (Which of the following is entirely correct?) OQ = 2.9 x 10-8 ppt forms O Q = 2.9 x 10-8, no ppt Q = 1.1 x 10-12, ppt forms O Q - 1.1 x 10-12, no ppt O Q = 4.4 x 10-12, no ppt
if 125 mL of a solution containing 0.0400 M of Pb(NO3)2 (aq) is mixed with 75.0 mL of a solution containing 0.0200 of Na...
if 125 mL of a solution containing 0.0400 M of Pb(NO3)2 (aq) is mixed with 75.0 mL of a solution containing 0.0200 of NaCl(aq), will there be a precipitate? PbCl3 has a Ksp value of 1.6 x 10^-5. Assume volumes are additive when mixed
When 0.10 L of 8.0 x 103M Pb(NO3)2 is mixed with 0.40 L of 5.0 x...
When 0.10 L of 8.0 x 103M Pb(NO3)2 is mixed with 0.40 L of 5.0 x 10-3M Na2SO4, will a precipitate form? (Ksp for PbSO4-6.3 x 107) PbSO4(s) = Pb2+ (aq) + SO42-(aq) O yes because Q<Ksp yes because Q> Ksp Ono because Q > Ksp Ono because Q<Ksp no because Q - Kup
solution 15 made containing 7.8 x 10-3 (Sr(NO3)2) 25.) suppose and 8.3 x10-2 NaF (aq). Calculate...
solution 15 made containing 7.8 x 10-3 (Sr(NO3)2) 25.) suppose and 8.3 x10-2 NaF (aq). Calculate Q and determine wheter a precipate lydstupem of SrFe will form. Ksp of SrF2= 2.8x10-9 ppt forms forms no ppt CQ = 2.0 110-4 pot forms ppt no ppt e Q= 6.1810-4 a. Q = 5.0 x10-5 b Q = 5.0 X1D-5 d Q = 6.1 810-4
If 300 mL of some Pb(NO3)2 solution is mixed with 600 mL of 2.70 x 10−2...
If 300 mL of some Pb(NO3)2 solution is mixed with 600 mL of 2.70 x 10−2 M NaCl solution, what is the maximum concentration of the Pb(NO3)2 solution added if no solid PbCl2 forms? (Assume Ksp = 2.00 x 10−5 M at this temperature.) Enter the concentration in M.
If 250 mL of some Pb(NO3)2 solution is mixed with 450 mL of 5.90 x 10−2...
If 250 mL of some Pb(NO3)2 solution is mixed with 450 mL of 5.90 x 10−2 M NaCl solution, what is the maximum concentration of the Pb(NO3)2 solution added if no solid PbCl2 forms? (Assume Ksp = 2.00 x 10−5 M at this temperature.) Enter the concentration in M.
If 400 mL of some Pb(NO3)2 solution is mixed with 400 mL of 1.10 x 10-2...
If 400 mL of some Pb(NO3)2 solution is mixed with 400 mL of 1.10 x 10-2 M NaCl solution, what is the maximum concentration of the Pb(NO3)2 solution added if no solid PbCl2 forms? (Assume Ksp = 2.00 x 10-5 M at this temperature.) Enter the concentration in M. Submit Answer Tries 0/99
Question 25 (4 points) Solutions of Pb(NO3)2 and NaCl are mixed to form a solution with...
Question 25 (4 points) Solutions of Pb(NO3)2 and NaCl are mixed to form a solution with final concentrations 0.01 M of Pb(NO3)2 and 0.025 M of NaCl. What will happen once these solutions are mixed? For PbCl, Ksp = 1.7 x 10-5. Sodium nitrate will precipitate, leaving an unsaturated solution of PbCl2 Nothing will happen, there will be no precipitate. Lead chloride will precipitate out of solution, leaving an unsaturated solution of PbCl2 Lead chloride will precipitate out of solution,...
QUESTION 1 43.2 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 36.1 mL of 0.415...
QUESTION 1 43.2 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 36.1 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)2 (aq) + 2 NaCl (aq) --> PbCl2 (s) + 2 NaNO3 (aq) How many moles of PbCl2 are formed? (with correct sig figs) QUESTION 2 What volume (in mL!!!) of 1.28 M HCl is required to react with 3.33 g of zinc (65.41 g/mol) according to the following reaction? Zn(s) + 2 HCl (aq)...
Suppose a solution is made containing 7.3 x 10-3 M Sr(NO3)2(aq) and 8.3 x 102 M NaF (aq). Calculate Q and determine whether a precipitate of SrF2 (s) will form. (In other words, which of the following is entirely correct?) Ksp of SrF2 = 2.8 x 10-9 a. Q = 5.0 x 105, ppt forms b. Q = 5.0 x 10-5, no ppt c. Q = 2.0 x 104 ppt forms d. Q = 6.1 x 104.ppt forms e. Q...
Will a ppt of SrF2 (s) form if you mix 7.7 x 10-4 M Sr(NO3)2 (aq) with 3.8 x 10-5 M NaF (aq)? (Which of the following is entirely correct?) OQ = 2.9 x 10-8 ppt forms O Q = 2.9 x 10-8, no ppt Q = 1.1 x 10-12, ppt forms O Q - 1.1 x 10-12, no ppt O Q = 4.4 x 10-12, no ppt
When 0.10 L of 8.0 x 103M Pb(NO3)2 is mixed with 0.40 L of 5.0 x 10-3M Na2SO4, will a precipitate form? (Ksp for PbSO4-6.3 x 107) PbSO4(s) = Pb2+ (aq) + SO42-(aq) O yes because Q<Ksp yes because Q> Ksp Ono because Q > Ksp Ono because Q<Ksp no because Q - Kup
solution 15 made containing 7.8 x 10-3 (Sr(NO3)2) 25.) suppose and 8.3 x10-2 NaF (aq). Calculate Q and determine wheter a precipate lydstupem of SrFe will form. Ksp of SrF2= 2.8x10-9 ppt forms forms no ppt CQ = 2.0 110-4 pot forms ppt no ppt e Q= 6.1810-4 a. Q = 5.0 x10-5 b Q = 5.0 X1D-5 d Q = 6.1 810-4
If 400 mL of some Pb(NO3)2 solution is mixed with 400 mL of 1.10 x 10-2 M NaCl solution, what is the maximum concentration of the Pb(NO3)2 solution added if no solid PbCl2 forms? (Assume Ksp = 2.00 x 10-5 M at this temperature.) Enter the concentration in M. Submit Answer Tries 0/99
Question 25 (4 points) Solutions of Pb(NO3)2 and NaCl are mixed to form a solution with final concentrations 0.01 M of Pb(NO3)2 and 0.025 M of NaCl. What will happen once these solutions are mixed? For PbCl, Ksp = 1.7 x 10-5. Sodium nitrate will precipitate, leaving an unsaturated solution of PbCl2 Nothing will happen, there will be no precipitate. Lead chloride will precipitate out of solution, leaving an unsaturated solution of PbCl2 Lead chloride will precipitate out of solution,...
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