Question

2 m Collar mass = 0.6 kg. It is released from rest at point A and moves down along frictionless vertical rod. Neglect size of collar and diameter of rod. Spring has natural length of 1.6 m and a spring constant of k = 30 N/m. Draw FBD of collar at position between A and C. Specify conditions where collar achieves max vertical displacement s. Use work and energy methods to determine max displacement s. S k = 30 N/m wa

Answer 1

2m 13 8 www K=30 N/m K (2-16) mg Nork done by spring forel @mmum FBD of Collan at a FBD of collar at ac mg. work done by Gravity foree Wg = mgs = 0.689.8188 Wb={* ((1 8444 -16) Wg =-15[8274 -3.2 V8++4 +2.56-0.16] Ws=-15[32-3.2 V84+4 +6.4 K(V8274 -116) N L! -> Wg 5.8868 (2+16)]

for work and Energy method (maximum value of s) work done by total force = Chonge in kinetic Energy =) Wg the FO 5.8868 - 15 ( 82-3.2, 32+4 +6.4) > 82 82-3.2 V8279 +6:45 0.39248 3 82 -3.2 V8279 -0.392483-6.4. 8= 1.408 M C Answer DOS TREK

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