Question

3. For the beam in Figure 2 below, using the work-energy method to solve the problem. (a) (10 points) Compute the slope at A. (b) (10 points) Compute the slope at B. 3 kips/ft 85 kip. ft B 15' .. 15' Figure 2.

Answer 1

ans corsk energy method or virteal wook method 3 kips/ft 85 kip. ft E Mat c = 0 B >a Fay Ay *30 – 3X15* 225 +85=0 15' 15' fey Ay= 30-917 KA for o2n< 15 3k/Ft Ma 1994 Ma = 30.91 731- 3x21: W 4 30.917 2 Mn- 309172-1.5x? ♡ 15<< 30 3K/FI LI Ma = 30.917a 45 CX-705) M= 337.5-14.083 x 9 30 151 30. 917 E21-75 ① for for slope at A apply unit moment at A I go 22 30 Slot r Y3o as per work energy method IOA mmda CE = S 30 IS (30-9173-1:542)(1-9/30) dae (337.5-(4:0333) Cl-. )dan OA - + EC O 15 1473.44 El 2 А

slope at B apply unit moment at B m 1 t 430 m = - - 2/30 |- 2²0 my - 7 as per work energy method l'Og - S mmaa GE 30 (337.5-14:0331) (1-9) dan 9 OB (30-9173-1:512) (-30) da EC + Сс 15 —va OB -317.185 EL mean opposite to unit moment OB 317.185 JOB وا