Question

find dimensions of a triangular shape given lenght and a right triangle 12 inch legs

Answer 1

SOLUTION;

ABC is right angle triangle

Where A angle is right angle

And according to question c= 12 inches

C= hypotenuse

Suppose other two side is x,

So, a=b=x

Now,

$c^{2}=a^{2}+b^{2}$

$(12)^{2}=x^{2}+x^{2}$

$(12)^{2}=2x^{2}$

inches

I = V72

Now, area of triangle is

$A= \frac{1}{2}(base)(height)$

$A= \frac{1}{2}(x)(x)$

$A= \frac{1}{2}(x^{2})$

$A= \frac{1}{2}(72)$

A=36 inch^​​​2

Dimensions of triangle is

$12 inch, \sqrt{72} inch, \sqrt{72} inch,$