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A triangular-shaped panel is to be machined. Two sides are given as 13.800 inches and 11.400 inches with an included angle of

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А 72-5 b SO 13.8 B 0 By Cosine Rule COA = 6²+6² at 2bc cos (72-5= (17.4)*+ (13-8² - a² 2(1):4) (13.8) 2 0 3007 129.96 + 190,4.. sinB = sin (72-5) x 11.4 15.026 0.72357 Be zin (0-72 357) <B=46.35 ZA+ CB+20= 180 72-5+ 46.35+2=18 Lo= 6l.is པ|

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