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Fill in the table below with the information for the first 3 subnets in the Class B Network 172.16.16.0 /20 (2+4 marks) Note:

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Answer #1

Total # of subnet=3

So subnet ID bits = ceil (log 3) =2 bits.

This 2 subnet bits is going to be 21st and 22nd bit of the given IP address since the first 20 bits are network ID bits which is given by /20 notation.

172.16.16 6.0/20 Subnet ! Subneta Subuet3 Networkl 10101100 00010000 DOO100 00 00 00 00 10101100 00010000 Oud Ohoo 0000000010

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