To find the Thevenin's equivalent of circuit with respect to ZL, we first find the Thevenin voltage Vt.
For this we replace ZL by an open circuit and the modified circuit will be:
Being an open circuit, no current flows through inductor(j3). So, voltage drop across it is zero.
So, Thevenin voltage will be the voltage across 4 ohm resistor. To find this, we use voltage divider rule as:
Vt = voltage across 4 ohm resistor =
= 1.25141.34
V
Next step is to find Thevenin impedance Zt. For this, we replace
ZL by an open circuit and voltage source 290
by a short circuit. Modified circuit will be:
As per circuit, Zt = [(-j5)||4] + j3
= [-j20/(4 - j5)] + j3
= (-j20 + j12 +15)/(4 - j5)
= (15 - j8)/(4 - j5)
= 2.6523.26
ohm
and short circuit current Isc = Vt/Zt
= (1.25141.34)/(2.65
23.26)
= 0.47118.08
A
So, Vt = 1.25141.34
V
Zt = 2.6523.26
ohm
Isc = 0.47118.08
A
j312 -j52 HE 2290° V 412 ZL Find the Thevenin equivalent of the circuit with respect...
-j52 13.12 11 2290° V 412 ZL Find the Thevenin equivalent of the circuit with respect to 2. Express the answer in terms of the Thevenin voltage (Vr ), short-circuit current (is), and Thevenin impedance (Zr). Round answer to 2 decimal places, add trailing O's as needed Vr = ] 2 •V isc LI А Zr- •N2
Question 3 -j52 HE j312 2290° v 412 ZL Find the Thevenin equivalent of the circuit with respect to Z. Express the answer in terms of the Thevenin voltage (Vr), short-circuit current (ise), and Theveni Round answer to 2 decimal places, add trailing O's as needed. Vr = 2 V isc 2 с А Zra 2. 12 Question 4 a 1020° V 36-82 Vab m2 102 - 240° 102 - 120° V 36-8036-80 Vea lo с id Find the line...
Question 3 30 pts -j52 412 12 -90° A 3212 ZL Find the Thevenin equivalent of the circuit with respect to Z - Express the answer in terms of the Thevenin voltage (Vr), short-circuit current (ise), and Thevenin impedance (ZT). Round answer to 2 decimal places, add trailing o's as needed. 2 V 2 A Zr= 2 12
Question 3 30 pts 212 412 w 12 -90° A 4 -j512 32 Find the Thevenin equivalent of the circuit with respect to Zų. Express the answer in terms of the Thevenin voltage Vr), short-circuit current (isc), and Thevenin impedance (Zr). Round answer to 2 decimal places, add trailing O's as needed. Vr = ov 2 A ZT= 12
Question 3 30 pts 212 412 w 12 -90° A 4 -j512 32 Find the Thevenin equivalent of the circuit with respect to Zų. Express the answer in terms of the Thevenin voltage Vr), short-circuit current (isc), and Thevenin impedance (Zr). Round answer to 2 decimal places, add trailing O's as needed. Vr = ov 2 A ZT= 12
Question 2 30 pts 2290° A 412 2.12 220° V +-;512 j312 Find the SAE's for the assigned nodal voltages. Solve for the nodal voltages. Round answer to 2 decimal places, add O's as needed. Express magnitude as positive number and angle between +180º. Vi = U2 = 2 V V3 = 2 < v
Question 2 30 pts 2290° A 412 2.12 220° V +-;512 j312 Find the SAE's for the assigned nodal voltages. Solve for the nodal voltages. Round answer to 2 decimal places, add O's as needed. Express magnitude as positive number and angle between +180º. Vi = U2 = 2 V V3 = 2 < v
Question 2 30 pts 2290° A 412 -j52 내 j3 22 220V 322 Find the SAE's for the assigned nodal voltages. Solve for the nodal voltages. Round answer to 2 decimal places, add o's as needed. Express magnitude as positive number and angle between +180° V1 = 2 V V2 = 2 V V3 = Z -V
Find the Thevenin equivalent with respect to the terminals a,b
for the circuit(Figure 1)if v = 410 V , i = 18 A .Find the equivalent voltage.Express your answer with the appropriate units.
Find the Thevenin equivalent circuit external to the indicated
load
impedance ZL=10Ω∠0° connected across a-b as shown in
Figure 1. Also,
calculate the current through the impedance
ZL=10Ω∠0°
(a) Find the Thevenin equivalent circuit external to the indicated load impedance ZL=10 2Z0° connected across a-b as shown in Figure 1. Also, calculate the current through the impedance ZL 10 220° 24 Q 10 Q a + Z 10 Zo 5 VZ0° 16 Q 500 mA /0° b 12 Q Figure...