Question

Listed below we blood pressure measurements mmtaken from the dems of the same woman Asume that the pred sample data is a simple and spend the other benyom Use a 0 10 ficance level to test for a difference between the measurements from the two wms What can be conclude? Right arm 150 141 137 135 1. 167 172 179 152 146 Lefarm In the came the means of the differences or the people of a part of its where achandoutorence is depredeste moment to the right on the menuen rom het en When the modern houten ОА , , 0 OBIO ODIO HO CHO H 10 Identity the best statist 1 = - 400 Round to two decimal places as needed Identity the value Pv0015 Round to the decimal places as needed What is the conclusion based on the hypothesis ost? Since the Pos than the significance level the loss There on evidence lo sport team of december the two

Answer 1

Solution:- Ceciven data: Right arm 150 141 137 135 136 Left arm 167 17- 179 15 146 d -17 -31 -42- -17 means ह 17 5 = -23.4 d . s- । ndi n-1 - 3403 5* (-23.42 ५ 665.2 4 S 166 . 3 Si= 12.8957 Ics Scanned with CamSanner

The null and alternative hypothesis is .ch Hoi la=o Vs. H: Mato The test statistic is. ta alla Salin under Ho ta - 23.4 171.8957 / 5 t -4.0575 : : - 4. 05 To find p-value p-value = P(12 > 4.06 pflt! topeltis 4.0.6 P.(-406 < t 5.40G Р te çoi ) -P - 45-606) - 0.9923 0.9923-0.0077 cs Scanned with manner

- 0.9846 0.0154 P-value = 0.015 <d since the P-value is less than the Significance level, Reject the null hypothesis. There is sufficient evidence to support the claim difference in measurements between the two arms CS Scanner with Camscanner