Question

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(1 point) Archeologists have discovered a sample of ancient Egyptian skulls from 150 A.C. A sample of 5 Egyptian skull breadths (in mm) from 150 A.C. is show below: Skull breadths Sample: 132, 135, 137, 135, 135 Part 1: - Part 2 Using your answers from part 1 and the formula for a 95% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for calculating the confidence interval below. To enter a where x is any number, type sqrt(x). For example, v2 should be written as sqrt(2). 150 A.C. skull breadth: 1.7889 1.7889 134.8 - 2.776 to 134.8 +2.776 sqrt(5) sqrt(5) - Part 3 Using the formulas from part 2, find the 95% confidence intervals for the mean maximum skull breadths of all Egyptian skulls from 150 A.C. Round your answer to the nearest hundredth (2 decimal places). 150 A.C. skull breadths: to
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Answer 1

8.1) let the date as, n = 5 132, 135, 137, 135, 135. Ex= 674 X = 134.8 8 {(xi-x² 3.2 12.8 4 S= 1.989 2=0.05 & df = n-1= 5+1=4 critical tx, df = 2.776

c1= x I ta, df 95% c 1 for mean is. = 134.3 + 2.776 x 1,789 √5 = 13418 + 2.776 x 0.8 = 134.8 + 2.22 C 132.58, 137.02) 132.58 to 137,02 let, the data as given below, 27451 33788 29627 32924 24733 37382 40187 32237 24787 31460 36780 23901 38597 25858 37401 n=15, EX= 447207 x=31813.8 s² {(xi-x)² 431534680 82 = 30823905,7 S=5551.93 =0.06, d fan-1= 14. colical twind f = 2.046

94% CI for el is, x & te,df s 5551.93 31813, 8 I 2.046 × 15 31813.8 I 2.046 X 1433.5 31813.8 2933.19 ( 28880.61 34746.99) 7 28880.61 cu < 3446.99 9.3 let, the given data as below, .n 136, 124, 137, 122, 120, 119, n=6 X = 758 X = 126.33 S Ecxi-x2 325,33 15 65.6667 n-1 Is=8.07 x=0.01 df = 5 critical t = 4.03

99% CI for el is, X Į ta, da x S 126,33 1 4.03 X 8,07 126,33 € 4.03 X 3.29 126.33 + 13.26 ( 113.05 139.59 113.05 to 139.59