To calculate inverse Laplace transform convert the given function into standard functions. Solution is as -
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is 45-5 The inverse Laplace transform of F(s) = $?+9 Select the correct answer a. 4cos3t...
Question 24 The inverse Laplace transform of F(s)= 2s-3 s²+1 is Select the correct answer ©2cost-3sint 2cost+3sint cos(2t) -sin (36) -2cost-3sint -cos(26) + sin(36) < Previous
Find the inverse Laplace transform of the function F(s) s +1 $2 - 8s + 20 * uz(t)e(4t-12) (cos(2t – 6) + 2.5 sin(2t – 6)) OF U3(t)e4t (cos(2t – 3) + 0.5 sin(2t – 3)) OC e(4t-12) (cos(2t – 3) + sin(2t – 3)) OD uz(t) (cos(2t – 6) + sin(2t – 6)) ОЕ uz(t) (e4t – 5t)
QUESTION 24 Find the inverse Laplace transform of the following function. F(S) = s2-35 s4+10s2 +9 (3cos (3t)+sin (3t) -3cost-sint) B. (cos (3t)+sin (3t) -3cost-3sint) (cos (3t) +3sin (3t) -3cost-sint) (3 cos (3t) +3sin (3t) - 3 cost-sint) 1 E. (3 cos (3t) +sin (3t) -3cost-3sint)
Chapter 6, Section 6.6, Go Tutorial Problem 10 Find the inverse Laplace transform of the function using convolutions F(s) = - 1 (s + 1)?(52 + 25 z-{F(s)- 676e-(26t+2) z"{F(s)- 885 sin 5t + 338 Cos St + 676e-t(26+ + 2) {F(s)) -sin 5t 845 (F(s)) 338 -Cos 5t (F(s)) - Bås sin 5t - 338 cos cos 5t + 676 e*(26+ + 2) Click If you would like to Show Work for this question: Open Show Work
Please Show every step thank you. Question 4 Your answer is INCORRECT. Give the Laplace transform of f(x) = -2x2 – 3 + 3e3* cos(2x) - 3xe2x » ©F6)=-* 1) OF(S) ==* * = 5-65+ 13 6- 00F(0) - 4,2-68–13 6-232 b) +- 3s 32-65 +13 ( e) - . 3(3-2) s2 - 65 + 13 - S (S-2)2 1) None of the above. Question 5 Your answer is CORRECT. Give the inverse Laplace transform of F(s) = S-4 s(8...
D Question 5 D Question 7 20 pts Find the Laplace transform. £{/0) of the following function: Solve the following Initial Value Problem: " + 4y = sint - Ul(t - 2) sin(t - 2n), y(0) -0,(0) = 0 * (+64 +5) +ed (cos(36) + sin(5t)) None of the given answers is correct Owt) --sint + sin(2t) - (t - 2x)} sin(t - 2x) - sin(21 – 2*))] (t) = sint - sin(2) - 11(- 21) sin(-2) - sin(2t -...
Calculate the Laplace transform of the following time functions by applying the Laplace transform properties: f) f(t) = 3t cos(t) g) f(t) = 3t sin(3t) h) f(t) = 2te*** – 3t sin(t) i) f(t) = t sin(3t) + 2t cos(t) j) f(t) = 5sin(t)/(3t)
1 point) Consider the initial value problem dy 29y--9e cos( dt dt2 dt Write down the Laplace transform of the left-hand side of the equation given the initial conditions Y(sA2-10s+29)+3s-24 Your answer should be a function of s and Y with Y denoting the Laplace transform of the solution y. Write down the Laplace transform of the right-hand side of the equation -9(s-5(S-5)A2+9) Your answer should be a function of s only. Next equate your last two answers and solve...
(1 point) Find the inverse Laplace transform f(t) = C-' {F(s)} of the function F(s) = 2s - 3 32 + 16 560) = c { 2s - 3 32 + 16 = 2cos(4t)-2 sin(4) help (formulas)
QUESTION 12 Apply Laplace Inverse to find f(t): s +7 F(s) = 5(52 + 4s +3) Choose the correct answer: L-'[F(s)] = f() 1) f(1) = 4t’e-31 - 3e-+ + 7t 2) f(t) = 5t? - 3e-4 3) f(0) =2-31 - 3e-- + 4) f() = 6e-6 - e-31 +} QUESTION 13 Solve the ODE: 2 2 + 3ź - 2z = te-2 z(0) = 0 & ż(0) = -2 Choose the correct answer: 1) z(t) = -0.768 0.5t -...