Question

Find the irreducible polynomial of 1 + i over Q.
0 0
Add a comment Improve this question Transcribed image text
Answer #1

\large \\ \text{ Clearly , } 1+i\notin \mathbb Q\\ \text{ So there is no linear irreducible polynomial exists. The irreducible polynomial must have atleast degree 2}\\ x=1+i\\ (x-1)^2=-1\implies (x-1)^2+1=0\\ \text{ So } (x-1)^2+1=x^2-2x+2=0\\ \text{ So root of above equation is } 1+i \\ \text{ and we had find 2nd order polynomial which is force to be irreducible. Even rational root test support this .}\\\large \\ \text{ Rational Root test: Given}\\ a_nx^n+a_{n-1}x^{n-1}+....+a_0=0\\ \text{ with integer } a_i ;a_n\neq 0 \text{ Then every rational root of given polynomial is of forms } \frac{\pm \text{Factors of }a_0}{\pm \text{Factors of }a_n}\\\\ a_0=2,a_2=1\\\\ \text{ Divisor of } a_0=\pm1,\pm2\\\\ \text{Divisor of } a_2=\pm1\\\\ \text{We will check following rational numbers } \pm \frac{1,2}{1}\\\\ \text{ All possible roots are } : 1,-1,2,-2\\\\ p(x)=x^2-2x+2\\ p(1)=1,p(-1)=5,p(2)=2,p(-2)=10\\ \text{ So polynomial p(x) is irreducuble over } \mathbb Q.\\\\ \textbf { So irreducible polynomial of } 1+i \textbf{ is } x^2-2x+2 \textbf{ over } \mathbb Q

Add a comment
Know the answer?
Add Answer to:
Find the irreducible polynomial of 1 + i over Q.
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT