Question

Through Geogebra (or any other geometry application): Beginning with two points A and B such that the length of AB = 1, construct a segment of length ⁴√5 using AB and geometry.

Answer 1

I shall explain method to construck 45 geometrically You can easily construct it by compass and straight edge. Slep I: Draw Number line using any unt and mark o, 1, 2, 3, See Tigel) figli) 0 А 7 + 3 4 1 2 Through the point A draw a line hall at a 2 ares 2 13 perpendicular This can be done by drawing a circle and meeting point as follows. See Trg (2) (ale first draw a circle centred Fig (2) at a meeting the number line * at from B and C. points B and C draw a ares of equal radius to meet at D 3.). Draw the line AB Mark the point E this line such that 44 = 16 (four times mark € uring compass or divider.) Slep IV : Draw the line segment oD and draw an are centered at o with radius OD cut the number line to the А right side of to get the point F. OF = √ 4² + 16² =ſso : 116x5 = 405 F represents in the number line corresponding to the number 405. OA We can Figl 3) SA 16 A 455 the point 0 4. Lee Fig (3)