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Calculate the quantity of heat absorbed by 12 g of water that warms from 30°C to 82 °C Express your answer to two significant
J are required to heat 283 g of water from 28 °C to 88 °C? The specific heat of water is 4.184 J/ How many (g°C)
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o since, specific heat of water (3) = 4.184I gc Heat ab sorbace m5 DT = - (129) x 4.184 8 (82-30) & go 2610.82 J let Q is req

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