Question

Help Cente? An experimenter examining decision-making ability asked 10 children to solve as many problems as they could in 10 minutes. One group was told that this was a test of their innate problem-solving ability; a second group was told that this was just a time- filling task. a. Does the mean number of problems solved differ between the two groups? Perform the correct hypothesis test with a - 05 using the 5 steps. Innate Time- filling 4 11 5 6 8 9 3 7 7 9 b. How large is the treatment effect? Answer this using percentage of variance explained and provide a brief explanation. c. Are the variances homogenous? Numerically justify your answer. HTML Editore BIVA-A- IEE2X ST 6

Answer 1

ANSWER:-
1 (A). Ho i M1-M2=0 Hai Mq - M2 to Level do significance, 2=0.85 Sample #1 - - 1 mean of sample 1, X=5.40 Standard deviation of sample 1, S1 = 2.073644135 Size of sample 1, n1 =5 Sample #2 ---> 2 mean of sample 2, X2 = 8.400 standard deviation of sample 2, S2 =1.95 Size of sample 2, n=5 difference in sample means = X-Az = 5.400 -8.4000 -3.0ooo

- Std eston, SE - Mež/n2+52/12) = 1:2728 t-Statistic. - (691-72). - Md)]SE |-3-0000/1.2728) = -2-3570 Degree of freedom =7 P-value = 8:0506 lexcel function : =T-DIST-27 t stat, -,de)) conclusion: P-value >d, Do not reject null hypothesis Effect size = El le+df) 8 = 0.410 Null and alternative hypothesis: Hoio = 0 Hii orto

3 Test statistica Fashish - = 4301,476131798601 [132.38 Degree of freedom: df, zn,-i = 4 df = R-124 P-value i P-value = 2*F-DIST.RT (13213843,4,4) =0.0ooo conclusion A.S P-value <a, We reject the null Hypothesis. Variances are not equal