Question

PHYSICS 1403 Lab Homework - Statics This homework will be due at 11:59 PM on Monday, August 3. The crew on Peg Leg Pete the Pirate's ship have mutinied. Now Pete finds himself walking the plank. The plank is 5.50 m long and has a mass of 18 kg. 3.60 meters of the plank extend out over the shark infested waters of the bay. The plank pivots on a small rail at the edge of the ship (3.60 m from the end of the plank that is over the water); this is the only point on the plank in direct contact with the ship. The remainder of the plank is held in place over the deck by metal bar. The bar is 1.10 m from the pivot. If Pete has a mass of 132 kg, what is the torque provided by the bar when Pete is at the end of the plank. (10 pts)

Answer 1

Perot point H R2 W 3 Wz W, W 4

foreque must be some force equilibre um; clock wise foreque as counter-clockwise fonque. W, We weight of plank left to perot point 13289.8 N man 1293. 6N weight of 3, 60 18 X X 908 N 115.5 N 5.50 W3 weight weight of plank reight to povot point ) X9.8 N. 18 x 1- 3.60 5.50 60.9 N 3.60 3,60 m 1.80m TG 1.90 0.95 m Mz lolom re 2

tch T2 un Ti = W. X Rei till + Zz f Tu (fore equilibrium ) 11 => w, rę t Worą W3 e tų 60.9 X 0.95 → 1293.6X 3.66 t 115.58 1.80 4807 Nm 4807 Nm torque will be provided by the bar.