Question

Score: 0 of 1 pt 1 of 18 (0 complete) 5.4.3 A population has a mean u = 71 and a standard deviation o = 30. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 243. (Simplify your answer.)

Answer 1

Solution :

Given that,

The sampling distribution of mean is ,

$\mu$
_T
= 71

The sampling distribution of standard deviation is ,  

$\sigma$
_T
= $\sigma$ / $\sqrt$ n = 30 / $\sqrt$ 243 = 1.9245