Question

This Question: 6 pts 2 of 18 (0 complete) A population has a means 134 and a standard deviation 30. Find the mean and standard deviation of the sampling distribution of sample means with sample stren51 The mean is and the standard deviation is o, (Round to three decimal places as needed.) wer in each of the answer boxes 1 Type here to search ote * a Twi

Answer 1

Solution:

Given:

Mean = $\mu = 134$

Standard deviation = $\sigma = 30$

We have to find mean and standard deviation of sampling distribution of sample mean.

Sample size = n = 51

Mean of sampling distribution of sample mean is:

$\mu_{\bar{x}}=\mu$

$\mathbf{{\color{DarkOrange} \mu_{\bar{x}}= 134}}$

Standard deviation of sampling distribution of sample mean:

Ox= n

$\sigma_{\bar{x}}= \frac{30}{\sqrt{51}}$

$\sigma_{\bar{x}}= \frac{30}{ 7.141428 }$

$\mathbf{{\color{DarkOrange} \sigma_{\bar{x}}= 4.201 }}$