Question

1. (5 pts] Write the equation of the line that contains the points in the table = mx + b). below in slope-intercept form (y х -3 -1 1 3 y 1.5 1 0.5 o

Answer 1

Solution:

Given table is  

  

x	-3	-1	1	3
y	1.5	1	0.5	0

Therefore the equation of the line is given by   

$y-1.5=\frac{1-1.5}{-1-(-3)}(x+3)\newline \implies y-\frac{3}{2}=-\frac{1}{4}(x+3)\newline \implies y=-\frac{1}{4}x-\frac{3}{4}+\frac{3}2\newline \implies y=-\frac{1}{4}x+\frac{3}{4}$

Which is in slope-intercept form, where the slope is

  $m=-\frac{1}{4}$

and   $b=\frac{3}{4}$ .