Question

2pt 01 M X-N(42,10) and X is computed from a random sample of size n=81, what is the distribution of 2pt Q2. If X-N(42,10) and X is computed from a random sample of size n=16, what is the distribution of a 2pt 23: When constructing a confidence interval for a mean, what are the two fundamentally different scenarios we would be working under? 2pt Q4 Interpret the following probability statement into a complete sentence: P(x-bar> 20.26) - 0.8084 2pt 05 Find the following probability P(Z > 0).

Answer 1

Pago 0 81 7 ECF) V (F) = N(18) h 0.17 XNN (42,10), n=81 Distribution of X is given al E (15) In E(X) = E(x) = 42 (*) n TONCH, orn) TNN (42, 1%81) 0.2) XQN (42,10), n=16 FGhIX) NECK) = E(X) = 42 InV) = N(X) = n? : TNN (42,1762 0.37 The selection of a confidence level for an intental न determines the probability that the confidance. interval produced will contain the true para meter value Confidence interval for mean el is given by CI For el = x + zx 5 (where, & varience in population n sample size sample mean etc are requirs For CI 0.47 pe > 20.26) = 0.8084 :: Sample meon () is exceeds or greater than 20.26) by 80.84 % 10 16 n * 2 7 confidence level 0.57 P(Z >0) = 1-PCzso) = 1 - 0 (0) from standard - 1-0. So Normal qable p(230)5 0.50