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A simple random sample of size n = 81 is obtained from a population with u = 70 and o = 27. (a) Describe the sampling distrib

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Answer #1

Given that, mean (μ) = 70 and standard deviation (\sigma) = 27

sample size (n) = 81

a) Since, the sample size is large, the sampling distribution of the sample mean (1) is approximately normal.

The mean and standard deviation of the sampling distribution of the sample means (1) are,

Hi = p = 70

27 01 3 이트 12 V81

b) We want to find, PT> 73

PT > 73) 73 – 70 = PC > 0 3 = P(Z > 1) = 1 - P(Z < 1) = 1-0.8413 = 0.1587

=> PT > 73) = 0.1587

c) We want to find, PT < 62.5)

PT < 62.5) = PC 62.5 – 70 - 0 3 = P(Z < -2.5) =1 - P(Z < 2.5) = 1-0.9938 = 0.0062

=> PT < 62.5) = 0.0062

d) We want to find, P(67.9<< 75.25)

75.25 – 70 P(67.9<> 75.25) 67.9 - 70 T - = PG 3 01 P(-0.7<7 < 1.75) 3 = P(Z < 1.75) – P(Z < -0.7) = 0.9599 – 0.2420 = 0.7179

=> P(67.9 <> 75.25) = 0.7179

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