for normal distribution z score =(X-μ)/σx | |
mean μ= | -1 |
standard deviation σ= | 11.5 |
a)
probability =P(X>7)=P(Z>(7--1)/11.5)=P(Z>0.7)=1-P(Z<0.7)=1-0.758=0.2420 |
b)
probability =P(X<-2)=(Z<(-2--1)/11.5)=P(Z<-0.09)=0.4641 |
c)
probability =P(X>12)=P(Z>(12--1)/11.5)=P(Z>1.13)=1-P(Z<1.13)=1-0.8708=0.1292 |
option D is correct
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