Solution:
The null and alternative hypothesis are
H0: 1
=
2
vs Ha :
1 <
2
denotes the pooled standard deviation.
= 1.3179
The test statistic t is given by
t =
=
= -2.295
Test statistic t = -2.295
Now ,
d.f. = n1 + n2 - 2 = 8 + 9 - 2 = 15
< sign in Ha indicates that the test is "One tailed left sided"
Use t table .
See the column of d.f.
Go to 15 d.f.
In the row of 15 , see where the value 2.295 fits in between.
It fits between 2.131 and 2.602
See the corresponding alpha values at ONE tailed
0.025 and 0.01
So , range of p value is 0.01 to 0.025
Answer is
E. Between 0.01 < p-value < 0.025
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