Question

Medical insurance status-covered (C) or not covered (N)—is determined for each individual arriving for treatment at a hospital's emergency room. Consider the chance experiment in which this determination is made for two randomly selected patients. The simple events are 04 - (C,C), meaning that the first patient selected was covered and the second patient selected was also covered, 02 - (C, N), 03 - (N,C), and 04 = (N, N). Suppose that probabilities are PO,) = 0.81, PCO2) = 0.09, P(Og) = 0.09, and P(O4) = 0.01. (a) What simple events are contained in A, the event that at most one patient is not covered? O A = {(C,C),(C, N), (N, N)} O A=((C,C), (N, C), (N, N)} O A = ((C, N), (N, C)} A = {(C, N), (N, C), (N, N)} O A = {(C, C), (C, N), (N, C)} Calculate PLA) P(A) = 0.19 X (b) What simple events are contained in B, the event that the two patients have different statuses with respect to coverage? O B = {(C,C), (C, N)} OB = {(C,C), (N, N)} O B = {(C, N), (N, C)} O B = {(C, N), (N, N)} O the empty set Calculate P(B) P(B) = 0.82 X

Answer 1

0.01 events are oq ={cc}, and PCO2) = 0.81 O2 = {CN}, P (2) = 0oog Og = {0,0}, p Cog) = 0.09 Ou = {N,N}, pca) a) event to represent that at most one patient is not recovered. Ast nost one patient is not recovered eithen one patient is not becovered both patients are recovered. so, simple events Contained in A are A = {CC,C),(CM), CNC)} Se, PCA) = 0081 +0.mq toooq= 0.99 meang on

b) event B represent that the two patients have different stocreses with respect to Covenage gift means it status of one Then status of and then patient is not covered se, simple erents contained in B patient is becovered ane B = { Cen),(^,c)} So, PB) = 0.09 +0.og o.18