Question

1. (-/2 Points] DETAILS PODSTAT6 6.E.023. MY NOTES ASK YOUR TEACHER Medical insurance status-covered (C) or not covered (N)-is determined for each individual arriving for treatment at a hospital's emergency room. Consider the chance experiment in which this determination is made for two randomly selected patients. The simple events are 0 - (C,C), meaning that the first patient selected was covered and the second patient selected was also covered, 02 - (C, N), 0, -(N, C), and 04-(N, N). Suppose that probabilities are P(O) = 0.81, PLO2) = 0.09, P(O3) = 0.09, and P(O4) = 0.01. (a) What simple events are contained in A, the event that at most one patient is not covered? A = {(C,C), (C, N), (N, N)} A = {(C,C),(N, C), (N, N)} O A = {(C, N), (N, C)} O A = {(C, N), (N, C), (N, N)} A = {(C,C), (C, N), (N, C) Calculate P(A). P(A) (b) What simple events are contained in B, the event that the two patients have different statuses with respect to coverage? OB = {(C,C), (C, N)) B = {(C, C), (N, N)} O B = {(C, N), (N, C)} B = {(C, N), (N, N)} the empty set Calculate PCB). P(B) = Need Help? Read It Watch It Talk to a Tutor

Answer 1

"_) A = sl cc) (CN) INCI] ablton ef PIAL Plcclt plcnit Pinc) 0:81 t UiOS O. Og ogg = Y.CNA Nch B option b y 0.0 g + 0:0S = PIB) 10:18