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question info in pic. please answer these questions

1. the work in kJ from state 1 to 3 is?

2. the specific internal energy at state 2 in kJ/kg is?

3. the heat transfer in kJ into the steam in the process from 1 to 2 is?

4. the heat transfer in kJ into the steam in the process from 2 to 3 is?
Two kilograms of water inside a piston-cylinder device undergoes the process from state 1 to 3, shown in the p V diagram belo
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Answer #1

Scolution : (xla) f T roula, Isoula I Pu 04 L 0.002106 (m3) IU for proceso 1-2, MT=PV It is a constant pressure process P=couA) PV = MRT MR IMT = PV R. 0.461 0.461 U = 4.18 *[Piv = 4.18 (150 X 0.002106] - 2.864 kJ/xg. Put the value of Ul into eah, U2

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