Question

Two Glograms of water inside a piston Cylinder device undergoes the process from state I to 3 shown in the pou diagram below. The initial Conditions at state o are pi= 150kpa and v=0.002106m. At the final state 3 are P3=200kpa and Uz = 0.4m². Tim) The heat transfer in KJ into the Steam in the process from 2 to 3 is closer to? a) 423 b) 569 - 755 a) 926 e) 1011 ) 280 g) 355 h 1124

Answer 1

- 47 pointi, - Dez 150 kPa, Vi= 0.002106 ms. __ mne 289 - Vo= 0.002106 = 0.0010.53 malaq From steam tableio- ___fou subcatwared - B=150 kPa Liquidéo- vez V2 V3 - 044 0.2m3/84 For 1508PA . r2 = Vft & (&q=&4). > On 2: O OO2053+x (1.1593 -0.001053). Tx= 0.172 7 . í hos hut acha bo) - 2166- 6+ oort=26976-46667 [h2 = 848.95 KJ/29 / s Scanned with Sama Seamer-

VWWAAV11LLLLLY 1919191919191 point & V = 0.2 m/aq ac 200 gpa _ _.=Yta + x( ng 3-V13) 02 = 0.001060+ «' (0-8856-0.001060) PT = 0.2257 also ho = 2705-72 he = 502.22J/89. " hat hit x' (ho-hi ___ = 804.2 + 0.295 (2201053) - h3 = 999.54 kJ/29 7 2 012 Heat transfer ios 2-3 Ah = MWC ha che) . 2C 999.54 -848095). 302 20 4 2 3 8 conste vor the overall rapi | "273: corses voreref ob. 302= ou + 0.7 (450 200-150). Scanngd wito Cám Scanner 180 = bultow au = 302-20 = 282xo Heat transfer I from is leni