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Let P3 have the inner product given by evaluation at -6, -1, 1, and 6. Let po(t) = 1, p1(t) = 2t, and P2 (t) = ? a. Compute t

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Answer #1

<P29) =P (-619(-6) + f(-1) 9(1) Ap(90)+166996). Po = 1, P, = 2t, Pa = t². <1,2t) = 12(-6) + 012(-1)+1.0(1) +1.2.(-6) 2 Heno P

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